Question 4

The conversion of molecules X to Y follows second order kinetics. If concentration of X is increased to three times how will it affect the rate of formation of Y?

Answer

The order of reaction is defined as the sum of the powers of concentrations In the rate law.

The rate of second order reaction can be expressed as rate = k [A]²

The reaction X → Y follows second order kinetics.

Therefore, the rate equation for this reaction will be:

Rate = k [X]^{2 ________________________}(1)

Let [X] = a mol L^-1, then equation (1) can be written as:

Rate = k [a]²

= ka²

If the concentration of X is increased to three times, then [X] = 3a mol L^-1

Now, the rate equation will be:

Rate = k [3a]²

= 9 (ka²)

Hence, the rate of formation will increase by 9 times.

10 Comment(s) on this Question

Lycky 2019-09-14 22:25:44

Thanks

Shalini kumari 2019-07-08 19:48:19

Thanks

Diksha 2019-07-07 07:16:56

Thanks

Diksha 2019-07-07 07:16:41

Thanks

Payal 2019-05-27 18:56:45

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Radhe 2019-05-13 12:18:02

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Bhola chhonker 2019-05-11 08:26:45

Thanks

Bhola chhonker 2019-05-11 08:26:18

Thanks

Diksha Mishra 2019-04-22 02:19:06

Thnk u so much

Harsh sharma 2019-03-11 22:22:04

Thnk you very much