Question 6

For the following equilibrium, K= 6.3 × 1014  at 1000 K

NO (g) + O3 (g) NO2 (g) + O2 (g)

Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc, for the reverse reaction?

Answer

It is given that Kfor the forward reaction is 6.3 × 1014  

Then, K for the reverse reaction will be,

K = 1 / Kc

     = 1 /  6.3 × 1014  

     = 1.59 x 10-15

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