Question 44

An ion with mass number 56 contains 3 units of positive charge and 30.4% more neutrons than electrons. Assign the symbol to this ion.

Answer

Let the number of electrons present in ion ,S3+ = x

∴ Number of neutrons in it = x + 30.4% of x = 1.304 x

Since the ion is tripositive,

⇒ Number of electrons in neutral atom = x + 3

∴ Number of protons in neutral atom = x + 3

Now mass number = no of protons + no of neutrons

56 = x + 3 + 1.304x

Or 2.304x = 53

Or x = 23

Therefore no of protons = atomic no = x + 3 = 23 + 3 = 26

∴ The symbol of the ion 

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