Question 11

Silver crystallises in fcc lattice. If edge length of the cell is 4.07 x 10-8cm and density is 10.5 g cm-3, calculate the atomic mass of silver.

Answer

From the equation, density = ZxM/a3 x N0, we get

M = ρ x a3 x N0/Z …………………………………1

Placing the values in equation 1,

WE GET M= 10.5 x (4.07 x10-8)3 x 6.022 x 1023/4

= 106.6 gmol-1

= Therefore, atomic mass of silver = 106.6 gmol-1

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