Question 21

Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell?

Answer

We know, for a fcc unit cell,radius of atom

r = a/2√2

Or

a = 2r√2

By putting the values of r &√2 we get

a = 2 x 0.144 x 1.414 = 0.407nm

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