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Question 6

\begin{align} \int \left(4e^{3x} + 1\right).dx \end{align}

Answer

\begin{align} \int \left(4e^{3x} + 1\right).dx \end{align}

\begin{align} =4\int e^{3x}.dx + \int 1.dx \end{align}

\begin{align} =4\left(\frac {e^{3x}}{3}\right) + x + C \end{align}

\begin{align} =\frac {4}{3} e^{3x} + x + C \end{align}

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