Question 10

\begin{align} \int \left(\sqrt{x} - \frac {1}{\sqrt{x}}\right)^2 .dx\end{align}

Answer

\begin{align} \int \left(\sqrt{x} - \frac {1}{\sqrt{x}}\right)^2 .dx\end{align}

\begin{align} =\int \left(x + \frac {1}{x} - 2\right) .dx\end{align}

\begin{align} =\int x .dx + \int \frac {1}{x} . dx - 2\int 1. dx\end{align}

\begin{align} =\frac{x^2}{2} + \log\left(\left|x\right|\right) - 2x + C\end{align}

 

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