Question 5

A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 ms–1. How long does the body take to stop?

Answer

Retarding force, F = -50 N

Mass of the body, m= 20 kg

Initial velocity of the body, u= 15 m/s

Final velocity of the body, v= 0

UsingNewton's second law of motion, the acceleration (a) produced in the body can be calculated as:

F= ma

-50 = 20 × a

∴ a  = -50 / 20  =  -2.5 m/s2

Usingthe first equation of motion, the time (t) taken by the body to come to rest can be calculated as:

v= u + at

∴ t  =  -u /a  =  -15 / -2.5   = 6s

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