Assign the position of the element havin | Class 11 Chemistry Chapter Classification of Elements and Periodicity in Properties, Classification of Elements and Periodicity in Properties NCERT Solutions

Current NCERT chapter

Academic session 2026-27, Chapter 3 in the current curriculum.

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Classification of Elements and Periodicity in Properties. This page offers a step-by-step solution to the specific question from Exercise 1, Question 30:

Assign the position of the element having outer electronic configuration

(i) ns2 np4 for n = 3 (ii) (n - 1)d2 ns2 for n = 4, and (iii) (n - 2) f7 (n - 1)d1 ns2 for n = 6, in the periodic table.

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 30:

Assign the position of the element having outer electronic configuration

(i) ns2 np4 for n = 3 (ii) (n - 1)d2 ns2 for n = 4, and (iii) (n - 2) f7 (n - 1)d1 ns2 for n = 6, in the periodic table.

Answer:

(i) Since n = 3, the element belongs to the 3rd period. It is a p–block element since the last electron occupies the p–orbital.

There are four electrons in the p–orbital. Thus, the corresponding group of the element

= Number of s–block groups (3s2) + number of d–block groups ([Ne]10 + number of p–electrons(3p4)

= 2 + 10 + 4

= 16

Therefore, the element belongs to the 3rd period and 16th group of the periodic table. Hence, the element is Sulphur ([Ne]103s23p4)

(ii) Since n = 4, the element belongs to the 4th period. It is a d–block element as d–orbitals are incompletely filled.

There are 2 electrons in the d–orbital.

Thus, the corresponding group of the element

= Number of s–block groups (4s2) + number of d–block groups (3d2)

= 2 + 2

= 4

Therefore, it is a 4th period and 4th group element. Hence, the element is Titanium ([Ar]183d24s2.

(iii) Since n = 6, the element is present in the 6th period. It is an f –block element as the last electron occupies the f–orbital. It belongs to group 3 of the periodic table since all f-block elements belong to group 3. Its electronic configuration is [Xe]54 4f7 5d1 6s2. Thus, its atomic number is 54 + 7 + 2 + 1 = 64. Hence, the element is Gadolinium.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Classification of Elements and Periodicity in Properties.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Niharika
  • Jul 18, 2018

It is a good source of niformation to the childern of 11 (Che)we expect you to keep more and more like this


  • Muskan
  • Sep 03, 2017

For (n-1)d1ns2


  • Mayank kumar
  • Nov 15, 2016

What is oxidation number of carbon's in CH3CH2O4


  • Mayank kumat
  • Nov 15, 2016

Really helpful. Thanks


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 30: Assign the position of the element having outer electronic configuration (i) ns2 np4 for n = 3 (i....

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