If A and G be A.M. and G.M., respectivel | Class 11 Mathematics Chapter Sequence and Series, Sequence and Series NCERT Solutions

Current NCERT chapter

Academic session 2026-27, Chapter 8 in the current curriculum.

Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter Sequence and Series. This page offers a step-by-step solution to the specific question from Exercise 3, Question 29:

If A and G be A.M. and G.M., respectively between two positive numbers, prove that the numbers are A plus-or-minus square root of open parentheses A plus G close parentheses open parentheses A minus G close parentheses end root
.

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 29:

If A and G be A.M. and G.M., respectively between two positive numbers, prove that the numbers are A plus-or-minus square root of open parentheses A plus G close parentheses open parentheses A minus G close parentheses end root
.

Answer:

It is given that A and G are A.M. and G.M. between two positive numbers. Let these two positive numbers be a and b.

∴ A M space equals space A space equals space fraction numerator a space plus space b over denominator 2 end fraction space space space space space space space space space space space space... left parenthesis 1 right parenthesis
G M space equals space G space equals space square root of a b end root space space space space space space space space space space space space space space space space... left parenthesis 2 right parenthesis

From (1) and (2), we obtain

a + b = 2A … (3)

ab = G2 … (4)

Substituting the value of a and b from (3) and (4) in the identity (a – b)2 = (a + b)2 – 4ab, we obtain

(a – b)2 = 4A2 – 4G2 = 4 (A2–G2)

(a – b)2 = 4 (A + G) (A – G)

open parentheses a minus b close parentheses space equals space 2 square root of open parentheses A plus G close parentheses open parentheses A minus G close parentheses end root space space space space space space space space space space... left parenthesis 5 right parenthesis

From (3) and (5), we obtain

2 a space equals space 2 A space plus space 2 square root of open parentheses A plus G close parentheses open parentheses A minus G close parentheses end root
rightwards double arrow a space equals space A space plus space square root of open parentheses A space plus space G close parentheses open parentheses A minus G close parentheses end root

Substituting the value of a in (3), we obtain

b space equals space 2 A space minus A space minus space square root of open parentheses A space plus space G close parentheses open parentheses A minus G close parentheses end root space equals space A space minus space square root of open parentheses A plus G close parentheses open parentheses A minus G close parentheses end root

Thus, the two numbers are A plus-or-minus square root of open parentheses A plus G close parentheses open parentheses A minus G close parentheses end root.

 


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Sequence and Series.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • abraham
  • Jul 14, 2018

thank u very much sir or madam


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Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 3 , Question 29: If A and G be A.M. and G.M., respectively between two positive numbers, prove that the numbers are&n....

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