A G.P. consists of an even number of ter | Class 11 Mathematics Chapter Sequence and Series, Sequence and Series NCERT Solutions
Current NCERT chapter
Academic session 2026-27,
Chapter 8 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter Sequence and Series. This page offers a step-by-step solution to the specific question from Exercise 5, Question 11:
A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of terms occupying odd places, then find its common ratio.
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With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.
Question 11: A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of terms occupying odd places, then find its common ratio.
Answer:
Let the G.P. be T1, T2, T3, T4, … T2n.
Number of terms = 2n
According to the given condition,
T1 + T2 + T3 + …+ T2n = 5 [T1 + T3 + … +T2n–1]
⇒ T1 + T2 + T3 + … + T2n – 5 [T1 + T3 + … + T2n–1] = 0
⇒ T2 + T4 + … + T2n = 4 [T1 + T3 + … + T2n–1]
Let the G.P. be a, ar, ar2, ar3, …
Thus, the common ratio of the G.P. is 4.
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Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 5 , Question 11: A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of terms ....
Comments
Thank u it was very helpfull
Its Helpful
Yes the process is correct and the answer as well,but there is a mistake.If it is taken that the original g.p is a,ar^2,a^3... the common ratio between the odd terms and even terms should be r^2.
Thank u
Thank you
it was very helpful!!!!