The principle of ‘parallax’ | Class 11 Physics Chapter Unit and measurment, Unit and measurment NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Physics - Chapter Unit and measurment. This page offers a step-by-step solution to the specific question from Exercise 1, Question 19: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 19:

The principle of ‘parallax’ in section 2.3.1 is used in the determination of distances of very distant stars. The baseline AB is the line joining the Earth’s two locations six months apart in its orbit around the Sun. That is, the baseline is about the diameter of the Earth’s orbit ≈ 3 × 1011m. However, even the nearest stars are so distant that with such a long baseline, they show parallax only of the order of 1” (second) of arc or so. A parsec is a convenient unit of length on the astronomical scale. It is the distance of an object that will show a parallax of 1” (second) of arc from opposite ends of a baseline equal to the distance from the Earth to the Sun. How much is a parsec in terms of metres ?

Answer:

Diameter of Earth's orbit = 3 × 1011 m

Radius of Earth's orbit, r = 1.5 × 1011 m

Let the distance parallax angle be1” = 4.847 × 10-6 rad.

Let the distance of the star be D.

Parsec is defined as the distance at which the average radius of the Earth's orbit subtends an angle of 1”.

∴ We have θ = r / D

Hence, 1 parsec  ≈ 3.09 × 1016 m.


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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 19: The principle of ‘parallax’ in section 2.3.1 is used in the determination of distances o....