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Academic session 2026-27, Chapter 4 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Physics - Chapter Laws of Motion. This page offers a step-by-step solution to the specific question from Exercise 1, Question 4:
One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is:
(i) T, (ii) T - mv2 / l , (iii) T + mv2 / l , (iv) 0
T is the tension in the string. [Choose the correct alternative].
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is:
(i) T, (ii) T - mv2 / l , (iii) T + mv2 / l , (iv) 0
T is the tension in the string. [Choose the correct alternative].
(i)
When a particle connected to a string revolves in a circular path around a centre, the centripetal force is provided by the tension produced in the string. Hence, in the given case, the net force on the particle is the tension T, i.e.,
F = T = mv2 / l
Where F is the net force acting on the particle.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 4: One end of a string of length l is connected to a particle of mass m and the other to a small peg on....
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