Question 7

It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

Answer

P (E) + P (not E) =1

P (E) + 0.992 = 1                  

P (E) = 1 - 0.992 = 0.008

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