One mole of an ideal gas at standard tem | Class 11 Physics Chapter Unit and measurment, Unit and measurment NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Physics - Chapter Unit and measurment. This page offers a step-by-step solution to the specific question from Exercise 1, Question 17: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 17:

One mole of an ideal gas at standard temperature and pressure occupies 22.4 L (molar volume). What is the ratio of molar volume to the atomic volume of a mole of hydrogen? (Take the size of hydrogen molecule to be about 1Å). Why is this ratio so large?

Answer:

Radius of hydrogen atom, r = 0.5 Å = 0.5 × 10-10 m

Volume of hydrogen atom = 4/3 π r3

= 4/3 x 22/7 x (0.5 x 10-10)3

= 0.524 x 1030 m3

1 mole of hydrogen contains 6.023 × 1023 hydrogen atoms.

∴ Volume of 1 mole of hydrogen atoms = 6.023 × 1023 × 0.524 × 10-30

= 3.16 × 10-7 m3

Molar volume of 1 mole of hydrogen atoms at STP,

Vm = 22.4 L = 22.4 × 10-3 m3

∴ Vm / Va  =  22.4 x 10-3  /   3.16 × 10-7  =  7.08 × 104

Hence, the molar volume is 7.08 × 104 times higher than the atomic volume. For this reason, the inter-atomic separation in hydrogen gas is much larger than the size of a hydrogen atom.

 


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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 17: One mole of an ideal gas at standard temperature and pressure occupies 22.4 L (molar volume). What i....