Two sitar strings A and B playing the no | Class 11 Physics Chapter Waves, Waves NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Physics - Chapter Waves. This page offers a step-by-step solution to the specific question from Exercise 1, Question 18: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 18:

Two sitar strings A and B playing the note 'Ga' are slightly out of tune and produce beats of frequency 6 Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3 Hz. If the original frequency of A is 324 Hz, what is the frequency of B?

Answer:

Frequency of string A, fA = 324 Hz

Frequency of string B = fB

Beat's frequency, n = 6 Hz

Beat's frequency is given as:

n = l fA +- fB l

6 =  324 +- fB

fB  = 330 Hz or 318 Hz

Frequency decreases with a decrease in the tension in a string. This is because frequency is directly proportional to the square root of tension. It is given as:

v ∝ Underroot T

Hence, the beat frequency cannot be 330 Hz

∴ fB = 318 Hz


Study Tips for Answering NCERT Questions:

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  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Waves.
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 18: Two sitar strings A and B playing the note 'Ga' are slightly out of tune and produce beats o....