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Read MoreWelcome to the NCERT Solutions for Class 12 Physics - Chapter Electric Charges and Field. This page offers a step-by-step solution to the specific question from Exercise 1, Question 10: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.
An electric dipole with dipole moment 4 × 10−9 C m is aligned at 30° with the direction of a uniform electric field of magnitude 5 × 104N C−1. Calculate the magnitude of the torque acting on the dipole.
Electric dipole moment, p = 4 × 10−9 C m (Given)
Angle made by p with a uniform electric field, θ = 30° (Given)
Electric field, E = 5 × 104 N C−1 (Given)
Torque acting on the dipole is given by the relation,
τ = pE sinθ
= 4 × 10-9 × 5 × 104 × sin 30
= 20 × 10-5 × 
= 10-4 Nm
Therefore, the magnitude of the torque acting on the dipole is 10−4 N m.
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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 10: An electric dipole with dipole moment 4 × 10−9 C m is aligned at 30° with the direct....
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What is the potential energy of the given problem?
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An electric dipole held at an angle of 300 with respect to a Uniform electric field of 4 x 104 N/C experiences a torque of 1.6 x10-25 Nm calculate its dipole Moment