An electric dipole with dipole moment 4 | Class 12 Physics Chapter Electric Charges and Field, Electric Charges and Field NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Physics - Chapter Electric Charges and Field. This page offers a step-by-step solution to the specific question from Exercise 1, Question 10: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 10:

An electric dipole with dipole moment 4 × 10−9 C m is aligned at 30° with the direction of a uniform electric field of magnitude 5 × 104N C−1. Calculate the magnitude of the torque acting on the dipole.

Answer:

Electric dipole moment, p = 4 × 10−9 C m (Given)

Angle made by p with a uniform electric field, θ = 30° (Given)

Electric field, E = 5 × 104 N C−1 (Given)

Torque acting on the dipole is given by the relation,

τ = pE sinθ

= 4 × 10-9 × 5 × 104 × sin 30

= 20 × 10-5 × 1 half

 

= 10-4 Nm

Therefore, the magnitude of the torque acting on the dipole is 10−4 N m.

 

 

 


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Comments

  • Hritik
  • May 31, 2019

Super


  • Dulen
  • May 20, 2019

What is the potential energy of the given problem?


  • Pawan
  • Apr 21, 2019

Nice


  • Bhumi
  • Apr 21, 2019

10^-4 kaise aaya hai


  • Sukriti
  • Apr 17, 2019

I was little bit confused


  • Rohan
  • Dec 01, 2018

Thank you so much


  • Sahil Singh
  • Oct 24, 2018

Ya it is too good


  • Keerthu
  • Apr 15, 2018

It is very nice


  • Ralynn
  • Apr 09, 2018

This is really good


  • rana singj
  • Dec 17, 2017

An electric dipole held at an angle of 300 with respect to a Uniform electric field of 4 x 104 N/C experiences a torque of 1.6 x10-25 Nm calculate its dipole Moment


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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 10: An electric dipole with dipole moment 4 × 10−9 C m is aligned at 30° with the direct....