The number density of free electrons in | Class 12 Physics Chapter Current Electricity, Current Electricity NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Physics - Chapter Current Electricity. This page offers a step-by-step solution to the specific question from Exercise 1, Question 13: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 13:

The number density of free electrons in a copper conductor estimated in Example 3.1 is 8.5 x 1028 m-3. How long does an electron take to drift from one end of a wire 3.0 m long to its other end? The area of cross-section of the wire is 2.0 x 10-6 m2 and it is carrying a current of 3.0 A.

Answer:

Number density of free electrons in a copper conductor, n = 8.5 × 1028 m - 3 Length of the copper wire, l = 3.0 m

Area of cross-section of the wire, A = 2.0 × 10 - 6 m2

Current carried by the wire, I = 3.0 A, which is given by the relation,

I = nAeVd

Where,

e = Electric charge = 1.6 × 10 - 19 C

Vd = Drift velocity 

Therefore, the time taken by an electron to drift from one end of the wire to the other is 2.7 × 104 s.


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Comments

  • Deep
  • Jan 24, 2019

Is it is correct?


  • AYYAPPA
  • Sep 13, 2018

Find out the number of electron


  • Nahdfah
  • Sep 11, 2018

Very dirty


  • magesh
  • May 01, 2018

answer value unimaginably large time. Can you please make me understand it ?


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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 13: The number density of free electrons in a copper conductor estimated in Example 3.1 is 8.5 x 1028 m-....