At 300 K, 36 g of glucose present in a l | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter Solutions. This page offers a step-by-step solution to the specific question from Exercise 2, Question 22: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 22:

At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

Answer:

Here we have given

π1= 4.98

π2 = 1.52

C1 = 36/180

C2 = ? (we have to find)

Now according to van’t hoff equation

Π = CRT

Putting the values in above equation,we get

4.98 = 36/180RT ------------------------1

1.52 = c2RT       ------------------------2

Now dividing equation 2 by 1 ,we get

(c2 x 180) / 36 = 1.52 / 4.98

or

c2 = 0.061

Therefore concentration of 2nd solution is 0.061 M


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Comments

  • Nevil
  • Aug 24, 2019

Nyc


  • Uzair shaikh
  • Jun 09, 2019

C1=mole/volume=weight/molecular weight × 1/volume = 36/180 × 1/1


  • manisha
  • May 28, 2019

what is the meaning of writing C1= 36/180 but its real value is 36g


  • Khushi
  • May 15, 2019

How can write 36/180


  • Obd
  • May 14, 2019

Sir its 0.061


  • RAUSHAN KUMAR
  • Apr 10, 2019

How write 36/180


  • Chandan Sharma
  • Sep 17, 2018

Sorry... The answer of this question is... 0.06 not 0.006


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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 22: At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If....