Which of the 3d series of the transition | Class 12 Chemistry Chapter The d-and f-Block Elements, The d-and f-Block Elements NCERT Solutions

Current NCERT chapter

Academic session 2026-27, Chapter 4 in the current curriculum.

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter The d-and f-Block Elements. This page offers a step-by-step solution to the specific question from Exercise 1, Question 3:

Which of the 3d series of the transition metals exhibits the largest number of oxidation states and why?

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 3:

Which of the 3d series of the transition metals exhibits the largest number of oxidation states and why?

Answer:

Mn (Z = 25) = 3d5 4s2

 Mn+2 is the most stable ion for manganese, the d-orbital can be made to remove 0 to 7 electrons. Compounds of manganese therefore range from Mn(0) as Mn(s), Mn(II) as MnO, Mn(II,III) as Mn3O4, Mn(IV) as MnO2, or manganese dioxide, Mn(VII) in the permanganate ion MnO4-, and so on. Mn has the maximum number of unpaired electrons present in the d-subshell (5 electrons). Hence, Mn exhibits the largest number of oxidation states, ranging from +2 to +7.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about The d-and f-Block Elements.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Prince Shriwastawa
  • Aug 21, 2019

But fe has 8 unpaired electron Why they not


  • Sakshi
  • Jan 25, 2019

Thanks


  • satvir singh
  • Jan 28, 2016

oxidation number or state is defined as the charge present on an atom or ion. in case of transition metals, there are five orbitals in the d subshell . when the number of unpaired valence electrons increases, the d-orbital increase & the highest oxidation state increases. This is because unpaired valence electrons are unstable and ready to bond with other chemical species,ie, the oxidation states wwill be the highest in the very middle of the transition metal periods due to the presence of the highest number of unpaired valence electrons.this is the reason why Mn has largest number of oxidation state in its period


  • rockstar
  • Jan 28, 2016

please write full answers


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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 3: Which of the 3d series of the transition metals exhibits the largest number of oxidation states and ....

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