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This chapter belongs to a previous NCERT/CBSE curriculum and is not part of the current 2026-27 chapter list. Removed in 2026-27.
Welcome to the NCERT Solutions for Class 9 Science - Chapter Gravitation. This page offers a step-by-step solution to the specific question from Exercise 0, Question 17:
On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?
The one which was simply dropped down will reach the ground first. If the height was large enough and measurements very accurate the earth continues to spin. Therefore, this stone will fall directly in a straight line joining the initial point on the centre of the earth but the point on the earth’s surface which was directly below the initial point will have moved. The vertical component of velocity of the other stone, which had been hurled parallel to the earth’s surface, is zero.
However, owing to the sphericity of the earth’s surface together with earth’s spin, it will have to fall greater distance in order to reach earth’s surface. Therefore, it will take longer.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 0 , Question 17: On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface w....
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