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Question 8

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm-1. Calculate its molar conductivity.

Answer

Given, k = 0.0248 S cm - 1

c = 0.20 M

Molar conductivity, Am =  (k x 1000) / c

= 0.0248 x1000 / 0.20

124 Scm2 mol - 1

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