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Question 9

The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 x 10-3 S cm-1.

Answer

Given,

Conductivity, k = 0.146 × 10 - 3 S cm - 1

Resistance, R = 1500 Ω

Cell constant = k × R = 0.146 × 10 - 3 × 1500

= 0.219 cm - 1

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