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The Solid State
Classify the following solids in different categories based on the nat...

Classify the following solids in differe | Class 12 Chemistry Chapter The Solid State, The Solid State NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter The Solid State. This page offers a step-by-step solution to the specific question from Exercise 1, Question 6: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 6:

Classify the following solids in different categories based on the nature of intermolecular forces operating in them:
Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide.

Answer:

Potassium sulphate → Ionic bond is formed, wherein potassium loses electrons & sulphate gains electrons.

Tin → Tin can form two ions Sn 2+ or Sn 4+ now depending on what form it is in and what other element it is bonding with then only the type of bonding will be known.

Benzene → It comprises of sp² hybridized carbon atoms which makes covalent bond with each other by mutual sharing and pairing of electrons.

Urea → Polar molecular solid and they mostly forms hydrogen bond with other atoms.

Ammonia → Covalently bonded polar compound formed by mutual sharing and pairing of electrons between nitrogen and three hydrogen atoms.

Water → Covalently bonded polar compound formed by mutual sharing of electrons between oxygen and hydrogen atoms.

Zinc sulphide → It exist in the form of crystals and makes coordination bond.

Graphite → It consist of carbon atoms and have covalent bond between them forming a 2-D (flat, planar etc.) network, which in itself is strong. These planes are then held together by London Forces, which are very weak.

Rubidium → Metallic bond is formed by rubidium because it is a metal. Metallic bond is hydride of covalent bond and ionic bond.

Argon → Non-polar molecular solid

Silicon carbide → Covalent or network solid

Other Questions of Chapter The Solid State

Ionic solids conduct electricity in molten state but not in solid state. Explain.

What type of solids are electrical conductors, malleable and ductile?

Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

If the radius of the octachedral void is r and radius of the atoms in close packing is R, derive relation between r and R.

Classify the following as amorphous or crystalline solids:
Polyurethane, naphthalene, benzoic acid, teflon, potassium nitrate, cellophane, polyvinyl chloride, fibre glass, copper.

Why do solids have a definite volume?

Why are solids rigid?

Explain how much portion of an atom located at

(i) corner and

(ii) body-centre

of a cubic unit cell is part of its neighbouring unit cell.

What type of stoichiometric defect is shown by:

(i) ZnS

(ii) AgBr

Classify each of the following as being either a p-type or an n-type semiconductor:

(i) Ge doped with In

(ii) B doped with Si.

Popular questions of class 12 Chemistry

How the following conversions can be carried out?

(i) Propene to propan-1-ol

(ii) Ethanol to but-1-yne

(iii) 1-Bromopropane to 2-bromopropane

(iv) Toluene to benzyl alcohol

(v) Benzene to 4-bromonitrobenzene

(vi) Benzyl alcohol to 2-phenylethanoic acid

(vii) Ethanol to propanenitrile

(viii) Aniline to chlorobenzene

(ix) 2-Chlorobutane to 3, 4-dimethylhexane

(x) 2-Methyl-1-propene to 2-chloro-2-methylpropane

(xi) Ethyl chloride to propanoic acid

(xii) But-1-ene to n-butyliodide

(xiii) 2-Chloropropane to 1-propanol

(xiv) Isopropyl alcohol to iodoform

(xv) Chlorobenzene to p-nitrophenol

(xvi) 2-Bromopropane to 1-bromopropane

(xvii) Chloroethane to butane

(xviii) Benzene to diphenyl

(xix) tert-Butyl bromide to isobutyl bromide

(xx) Aniline to phenylisocyanide

Give simple chemical tests to distinguish between the following pairs of compounds.

(i) Propanal and Propanone

(ii) Acetophenone and Benzophenone

(iii) Phenol and Benzoic acid

(iv) Benzoic acid and Ethyl benzoate

(v) Pentan-2-one and Pentan-3-one

(vi) Benzaldehyde and Acetophenone

(vii) Ethanal and Propanal

A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of 5% glucose in water if freezing point of pure water is 273.15 K.

A solution of glucose in water is labelled as 10% w/w, what would be the molality and mole fraction of each component in the solution? If the density of solution is 1.2 g mL^-1, then what shall be the molarity of the solution?

Henry's law constant for CO₂ in water is 1.67 x 10⁸Pa at 298 K. Calculate the quantity of CO₂in 500 mL of soda water when packed under 2.5 atm CO₂pressure at 298 K.

Calculate the mass of a non-volatile solute (molar mass 40 g mol^-1) which should be dissolved in 114 g octane to reduce its vapour pressure to 80%.

The vapour pressure of pure liquids A and B are 450 and 700 mm Hg respectively, at 350 K. Find out the composition of the liquid mixture if total vapour pressure is 600 mm Hg. Also find the composition of the vapour phase.

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

How many mL of 0.1 M HCl are required to react completely with 1 g mixture of Na₂CO₃ and NaHCO₃ containing equimolar amounts of both?

H₂S, a toxic gas with rotten egg like smell, is used for the qualitative analysis. If the solubility of H₂S in water at STP is 0.195 m, calculate Henry's law constant.

Recently Viewed Questions of Class 12 Chemistry

Henry's law constant for CO₂ in water is 1.67 x 10⁸Pa at 298 K. Calculate the quantity of CO₂in 500 mL of soda water when packed under 2.5 atm CO₂pressure at 298 K.

What are nucleic acids? Mention their two important functions.

What are the different oxidation states exhibited by the lanthanoids?

The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:

Experiment	A/ mol L^{- 1}	B/ mol L^{- 1}	Initial rate/mol L^{- 1} min^{- 1}
I	0.1	0.1	2.0 × 10^{- 2}
II	--	0.2	4.0 × 10^{- 2}
III	0.4	0.4	--
IV	--	0.2	2.0 × 10^{- 2}

Mention the conditions required to maximise the yield of ammonia.

Describe the oxidising action of potassium dichromate and write the ionicequations for its reaction with:

(i) iodide

(ii) iron

(II) solution and

(iii) H₂S

Write the structure of the major organic product in each of the following reactions:

How will you bring about the following conversions?

(i) Ethanol to but-1-yne

(ii) Ethane to bromoethene

(iii) Propene to 1-nitropropane

(iv) Toluene to benzyl alcohol

(v) Propene to propyne

(vi) Ethanol to ethyl fluoride

(vii) Bromomethane to propanone

(viii) But-1-ene to but-2-ene

(ix) 1-Chlorobutane to n-octane

(x) Benzene to biphenyl.

What is meant by hydroboration-oxidation reaction? Illustrate it with an example.

Write structures of the following compounds:

(i) 2-Chloro-3-methylpentane

(ii) 1-Chloro-4-ethylcyclohexane

(iii) 4-tert. Butyl-3-iodoheptane

(iv) 1,4-Dibromobut-2-ene

(v) 1-Bromo-4-sec. butyl-2-methylbenzene

Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

Read the question carefully and focus on the core concept being asked.
Reference examples and data from the chapter when answering questions about The Solid State.
Review previous year question papers to get an idea of how such questions may be framed in exams.
Practice answering questions within the time limit to improve your speed and accuracy.
Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

Sakshee
Jun 08, 2019

I m still confused about tin

satvir
May 11, 2015

tin mostly forms metallic bond with other atoms & because it exist in two oxidation states ,the metallic bonds so formed will be of different nature depending upon the oxidation state of tin. zinc sulphide shows polymorphism & exists in the form of crystals where they form coordination bond with other atoms.Coordination bond is one of the type of covalent bond where the bond is formed by sharing of electrons coming from form same atom only i.e the electrons involved in bonding comes from one of the atom & not from both of the atoms .

allu
May 10, 2015

Still confused about zinc sulphide and tin....lil more help plz!