Question 2

Find a cubic polynomial with the sum, sum of the product of its zeroes taken two at a time, and the product of its zeroes as 2, –7, –14 respectively.

Answer

                            Let the p(x) = ax3+bx2+ cx + d

                            Sum of zeroes and α, β and γ be the zeroes.

                            Then, α, β and γ = -b/ a = 2/1    …………………..(i)

                            αβ + βγ + γα= c/a = -7      …………………….(ii)



‘                           αβγ = -d /a = -14               ……………………………..(iii)

                            From equation (i), (ii) and (iii), we get

                            a = 1, b = -2, c = -7 and d = 14

                            Therefore, the required polynomial on putting the value of a, b, c and d is P(x) = x3 - 2x2 – 7x + 14

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