Class 12th Chemistry 2017 Set2 Delhi Board Paper Solution

Question 26

An element has atomic mass 93 g mol− 1 and density 11.5 gcm− 3 . If the edge length of its unit cell is 300 pm, identify the type of unit cell.

Answer

d = 11.5 gcm− 3

edge length (a) =  300 pm

atomic mass (M) = 93 g mol− 1 

d   =    Zm  /  a3 x Na

11.5 =  Z x 93  /  (300x10-10 cm) 3 x 6.022 x 1023

Z = 11.5 x 27x 10-24 x 6.022 x 1023  / 93

Z = 2.009 = 2

It is body centric cubic unit cell.

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