Henry's law constant for CO2 in water is 1.67 x 108Pa at 298 K. Calculate the quantity of CO2in 500 mL of soda water when packed under 2.5 atm CO2 pressure at 298 K.
It is given that:
KH = 1.67 × 108Pa
PCO2 = 2.5 atm = 2.5 × 1.01325 × 105Pa
= 2.533125 × 105Pa
According to Henry's law:
PCO2 = KHX
⇒ x = PCO2 / KH
= 2.533125 × 105 / 1.67 × 108
= 0.00152
We can write,
[Since, is negligible as compared to]
In 500 mL of soda water, the volume of water = 500 mL
[Neglecting the amount of soda present]
We can write:
500 mL of water = 500 g of water
=500 / 18 mole of water
= 27.78 mol of water
Now, nCO2 / nH2O = x
nCO2 / 27.78 = 0.00152
nCO2 = 0.042 mol
Hence, quantity of CO2 in 500 mL of soda water = (0.042 × 44) g
= 1.848 g
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(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
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Very good platform
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Nice explanation
Can be defined (O)2 oxigen
Good explanation. thanks
Nice and T.K for ur ans.
If quantity is 500ml,will you not divide it by 2?
Thanks nicely doneð
Mind blowing answer ððð