Question 2

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

Answer

Let the total mass of the solution be 100 g and the mass of benzene be 30 g.

∴ Mass of carbon tetrachloride = (100 - 30) g = 70 g

Molar mass of benzene (C₆H₆) = (6 × 12 + 6 × 1) g mol^{- 1}

= 78 g mol^{- 1}

∴ Number of moles of C₆H₆ =30/78 mol

= 0.3846 mol

Molar mass of carbon tetrachloride (CCl₄) = 1 × 12 + 4 × 35.5

= 154 g mol^{- 1}

∴ Number of moles of CCl₄ = 70/154 mol

= 0.4545 mol

Thus, the mole fraction of C₆H₆ is given as:

= 0.3846 / (0.3846 + 0.4545)

= 0.458

10 Comment(s) on this Question

Andria 2020-09-02 12:55:33

Thankyou sir

Bhanu 2019-12-28 10:03:06

Thanks

Sami sonare 2019-11-16 17:05:00

Thank you sir

Mohammadi Shafiya 2019-10-09 10:28:23

Thanks a lotð!

Rishabh Singh Rajput 2019-09-12 19:44:58

Thanks sir

Nidhi 2019-08-19 20:02:59

Really helpful âï¸

Prince 2019-07-18 17:08:00

MainBoling sir

Aaryan 2019-07-18 13:24:21

Which is solute nd solvent

Nasim akram 2019-07-15 20:19:02

Right Answer

Sakshi 2019-07-15 19:37:49

Thanks