Calculate the amount of carbon dioxide t | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Some Basic Concepts of Chemistry. This page offers a step-by-step solution to the specific question from Exercise 1, Question 4: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 4:

Calculate the amount of carbon dioxide that could be produced when

 

(i) 1 mole of carbon is burnt in air.

 

(ii) 1 mole of carbon is burnt in 16 g of dioxygen.

 

(iii) 2 moles of carbon are burnt in 16 g of dioxygen.

Answer:

The chemical equation for the reaction is:

 

 

i) when 1 mole of carbon is burnt in 1 mole(32 g) of air(dioxygen) ,then according to chemical equation (1) 1mole(44 g) of carbon dioxide is produced.

 

ii) 32g of Oxygen upon heating gives CO2 = 44g

1 g of Oxygen upon heating gives CO2 = 44/32

 

Therefore 16 g of Oxygen upon heating gives CO2 = 44/32*16 = 22 g

 

(iii) According to the question, only 16 g of dioxygen is available. It is a limiting reactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.

 


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Some Basic Concepts of Chemistry.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Aayush kumar
  • Jan 06, 2020

Explain part 3 plzzzzzzz


  • Pallavi
  • Sep 22, 2019

Explain part 3 clearly


  • Tanika
  • Sep 16, 2019

Please explain the 3rd part


  • Kalpana
  • Aug 28, 2019

Thanks


  • Nahidha
  • Aug 22, 2019

Please explain third one


  • Taeyhung
  • Aug 03, 2019

Answers of iii question is not elaborated


  • Harsh Singh
  • Aug 02, 2019

cant u explain this in equation form


  • Gu
  • Jul 30, 2019

Please give brief of part 3


  • Akash
  • Jul 28, 2019

Please explain clear


  • Kehkashan masroor siddiqui
  • Jul 20, 2019

Plz..explain 3rd part more clearly..


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 4: Calculate the amount of carbon dioxide that could be produced when   (i) 1 mole of carbon....