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Read MoreWelcome to the NCERT Solutions for Class 11 Chemistry - Chapter Structure of Atom. This page offers a step-by-step solution to the specific question from Exercise 1, Question 6: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.
Find energy of each of the photons which
(i) correspond to light of frequency 3× 1015 Hz.
(ii) have wavelength of 0.50 Å.
Planck’s quantum theory = Based on the assumption that all atoms on the surface of the heated solid vibrate at the frequency, Planck developed a model that came to be known as Planck’s equation. Through experiments of frequencies and temperature, Planck was able to generate a constant, Planck’s constant
h = 6.62607 x 10-34 J s
Using this constant he was able to restate his theory: energy was directly proportional to frequency. He wrote his equation as
E=hν
where E is energy, h is Planck’s constant, and v is frequency.
(i) Energy (E) of a photon is given by the expression,
E=hν
Where, h = Planck’s constant = 6.626 × 10–34 Js
ν = frequency of light = 3 × 1015 Hz
Substituting the values in the given expression E = hv we get
E = (6.626 × 10–34) (3 × 1015)
E = 1.988 × 10–18 J
(ii) Energy (E) of a photon having wavelength (λ) is given by the expression,
where , h = Planck’s constant = 6.626 × 10–34 Js
c = velocity of light in vacuum = 3 × 108 m/s
Substituting the values in the given expression of E:

Following results are observed when sodium metal is irradiated with different wavelengths.
Calculate (a) threshold wavelength and, (b) Planck’s constant.
| λ (nm) | 500 | 450 |
400 |
| v × 10–5 (cm s–1) | 2.55 | 4.35 | 5.35 |
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 6: Find energy of each of the photons which (i) correspond to light of frequency 3× 1015 Hz. ....
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You explained very simply...... so this is very usefull.... thank you alðð
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