Calculate the mass of sodium acetate (CH | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Current NCERT chapter

Academic session 2026-27, Chapter 1 in the current curriculum.

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Some Basic Concepts of Chemistry. This page offers a step-by-step solution to the specific question from Exercise 1, Question 5:

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 5:

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1

Answer:

0.375 M solution of (CH3COONa) = 0.375 moles(grams) of (CH3COONa) dissolved in 1000 ml of solvent.

 

But according to question ,we have to make a 500 ml solution of (CH3COONa)

 

∴Number of moles of sodium acetate in 500 mL

 

 

Molar mass of sodium acetate = 82.0245 g mole–1 (Given)

 

∴ Required mass of sodium acetate = (82.0245 g mol–1) (0.1875 mole)

 

= 15.38 g

 

 


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Some Basic Concepts of Chemistry.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Ridham Patel
  • May 29, 2020

Thank you


  • Tanu
  • May 24, 2020

Thanks a lot


  • Adi
  • Jul 21, 2019

Thanks for elaboration


  • Indranil
  • Jul 09, 2019

Thanks


  • Saumya
  • Jul 07, 2019

thanks for such good explanation


  • Prasoon
  • Jun 30, 2019

Supriti try to love


  • ravi
  • Jun 23, 2019

thnx


  • ravi
  • Jun 23, 2019

thanx


  • Sahil
  • Jun 18, 2019

Why we multi. 82.0245 with 0.1875 not divede


  • sakshi
  • Jun 05, 2019

Thank you but I want it a little more briefly


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 5: Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solut....

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