A pump on the ground floor of a building | Class 11 Physics Chapter Work Energy and Power, Work Energy and Power NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Physics - Chapter Work Energy and Power. This page offers a step-by-step solution to the specific question from Exercise 1, Question 15: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 15:

A pump on the ground floor of a building can pump up water to fill a tank of volume 30 m3 in 15 min. If the tank is 40 m above the ground, and the efficiency of the pump is 30%, how much electric power is consumed by the pump?

Answer:

Volume of the tank, V= 30 m3

Time of operation, t = 15 min = 15 × 60 = 900 s

Height of the tank, h= 40 m

Efficiency of the pump, n = 30%

Density of water, p = 103 kg/m3

Mass of water, m= pV= 30 ×103 kg

Output power can be obtained as:

P0  =  work done / Time  =  mgh / t

 =  30 x 103 x 9.8 x 40  / 900  = 13.067 x 103 W

For input power Pi,, efficiency n is given by the relation:

n =  P0 / Pi  = 30%

Pi  =  13.067 / 30 x 100 x 103

= 43.6 kW


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  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Work Energy and Power.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 15: A pump on the ground floor of a building can pump up water to fill a tank of volume 30 m3 in 15 min.....