A person trying to lose weight (dieter) | Class 11 Physics Chapter Work Energy and Power, Work Energy and Power NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Physics - Chapter Work Energy and Power. This page offers a step-by-step solution to the specific question from Exercise 1, Question 22: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 22:

A person trying to lose weight (dieter) lifts a 10 kg mass, one thousand times, to a height of 0.5 m each time. Assume that the potential energy lost each time she lowers the mass is dissipated. (a) How much work does she do against the gravitational force? (b) Fat supplies 3.8 x 107 J of energy per kilogram which is converted to mechanical energy with a 20% efficiency rate. How much fat will the dieter use up?

Answer:

(a) Mass of the weight, m = 10 kg

Height to which the person lifts the weight, h = 0.5 m

Number of times the weight is lifted, n = 1000

∴Work done against gravitational force:

= n(mgh)

= 1000 x 10 x 9.8 x 0.5

= 49 x 103J  = 49kJ

(b) Energy equivalent of 1 kg of fat = 3.8 × 107 J

Efficiency rate = 20%

Mechanical energy supplied by the person's body:

= 20/100 x 3.8 x 107 J

= 1/5 x 3.8 x 107 J

Equivalent mass of fat lost by the dieter:

= 1 / (1/5 x 3.8 x 107)  x 49 x 103

= 245 / 3.8 x 10-4

= 6.45 x 10-3 kg


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  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Work Energy and Power.
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 22: A person trying to lose weight (dieter) lifts a 10 kg mass, one thousand times, to a height of 0.5 m....