A hydrogen atom initially in the ground | Class 12 Physics Chapter Atoms, Atoms NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Physics - Chapter Atoms. This page offers a step-by-step solution to the specific question from Exercise 1, Question 6: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 6:

A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of the photon.

Answer:

For ground level, n 1 = 1

Let E1 be the energy of this level. It is known that E1 is related with n1 as:

E1 = -13.6/n12 eV

= -13.6/12 = -13.6 eV

The atom is excited to a higher level, n2 = 4.

Let E2 be the energy of this level.

∴ E2 = -13.6/n22 eV

= -13.6/42 = -13.6/16 eV

The amount of energy absorbed by the photon is given as:

E = E2 - E1

= (-13.6 /16) - (-13.6/1)

= 13.6 X 15/16 eV

= (13.6 X 15/16) X 1.6 X 10-19 = 2.04 X 10-18 J

For a photon of wavelengthλ, the expression of energy is written as:

E = hc/λ

Where,

h = Planck’s constant = 6.6 × 10−34 Js

c = Speed of light = 3 × 108 m/s

λ = hc/E

= (6.6x10-34x3x108)/(2.04x10-18)

= 9.7x10-8 m = 97 nm

And, frequency of a photon is given by the relation,

v = c/λ

= (3x108)/(9.7x10-8) ≈ 3.1 x 1015 Hz

Hence, the wavelength of the photon is 97 nm while the frequency is 3.1 × 1015 Hz.


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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 6: A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level.....