A 4.5 cm needle is placed 12 cm away fro | Class 12 Physics Chapter Ray Optics And Optical Instruments, Ray Optics And Optical Instruments NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Physics - Chapter Ray Optics And Optical Instruments. This page offers a step-by-step solution to the specific question from Exercise 1, Question 2: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 2:

A 4.5 cm needle is placed 12 cm away from a convex mirror of focal length 15 cm. Give the location of the image and the magnification. Describe what happens as the needle is moved farther from the mirror.

Answer:

Height of the needle, h1 = 4.5 cm

Object distance, u = −12 cm

Focal length of the convex mirror, f = 15 cm

Image distance = v

The value of v can be obtained using the mirror formula:

Hence, the image of the needle is 6.7 cm away from the mirror. Also, it is on the other side of the mirror.

The image size is given by the magnification formula:

Hence, magnification of the image, m = h2/h1 = 2.5/4.5 = 0.56

The height of the image is 2.5 cm.

The positive sign indicates that the image is erect, virtual, and diminished.

If the needle is moved farther from the mirror, the image will also move away from the mirror, and the size of the image will reduce gradually.


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Welcome to the NCERT Solutions for Class 12 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 2: A 4.5 cm needle is placed 12 cm away from a convex mirror of focal length 15 cm. Give the location o....