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Question 24

Consider a certain reaction A → Products with k = 2.0 x 10-2 s-1. Calculate the concentration of A remaining after 100 s if the initial concentration of A is 1.0 mol L-1.

Answer

k= 2.0 × 110-2 s-1

T= 100 s

[A]o= 1.0 moL - 1

Since the unit of kis s - 1, the given reaction is a first order reaction.

Therefore, k = 2.303/t  Log  [A]º / [A]

⇒2.0 × 110-2 s-1  = 2.303/100s  Log  1.0 / [A]

⇒2.0 × 110-2 s-1  = 2.303/100s  ( - Log [A] )

⇒ - Log [A] = -  (2.0 x 10-2 x 100)  2.303

⇒ [A] = antilog [-  (2.0 x 10-2 x 100)  2.303]

= 0.135 mol L - 1 (approximately)

Hence, the remaining concentration of A is 0.135 mol L - 1.

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