Class 12 Mathematics - Chapter Differential Equations NCERT Solutions | y = x2 + 2x + C : y'&
y = x2 + 2x + C : y' - 2x - 2 = 0
y = x2 + 2x + C
Differentiating both sides of this equation with respect to x, we get:
\begin{align}y^{'}=\frac{d}{dx}(x^2 + 2x + C)\end{align}
=> y' = 2x + 2
Substituting the value of y' in the given differential equation, we get:
L.H.S. = y' - 2x - 2 = 2x + 2 - 2x - 2 = 0 = R.H.S.
Hence, the given function is the solution of the corresponding differential equation.
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