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Question 1

A submarine emits a sonar pulse, which returns from an underwater cliff in 1.02 s. If the speed of sound in salt water is 1531 m/s, how far away is the cliff?

Answer

Time taken by the sonar pulse to return, t = 1.02 s

Speed of sound in salt water, v = 1531 m/s

Total distance covered by the sonar pulse = Speed of sound × Time taken

Total distance covered by the sonar pulse = 1.02 x 1531 = 1561.62 m                 ....(i)

Let d be the distance of the cliff from the submarine.

Total distance covered by the sonar pulse = 2d

⇒ 2d = 1561.62                          [From (i)]

⇒ d = 780.81 m

⇒ 2d = 1561.62

d = 780.81 m

 

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