Electromagnetic radiation of wavelength | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Structure of Atom. This page offers a step-by-step solution to the specific question from Exercise 1, Question 10: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 10:

Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. Calculate the ionisation energy of sodium in kJ mol–1.

Answer:

From E= hv or hc/ λ, we have λ = 242nm or 242 x 10-9m

C = 3 x 108 m/s

h = 6.62 x 10-34 Js

Now putting these values in the equation we get

E= (6.62 x 10-34 Js x 3 x 108 m/s) / (242 x 10-9m)

= 0.0821 x 10-17 J/atom

Or

E = (0.0821 x 10-17 ) / (1000 x 6.02 x 1023)

= 494 KJ/mol


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  • Read the question carefully and focus on the core concept being asked.
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Comments

  • Rahmat Fatima
  • Jul 14, 2020

Thq a lot to give this answers


  • Kanchan verma
  • Nov 14, 2019

I have problem in dealing with numerical


  • Varnika
  • Nov 12, 2019

Thank


  • Y
  • Jul 01, 2019

Y


  • Aisha
  • May 17, 2019

What about if use hydrogen instead of sodium


  • Priyanshi
  • Apr 23, 2019

Tq saralstudy


  • Aryan
  • Mar 24, 2019

Why cant we use -13.6Z^2


  • Aryan
  • Mar 24, 2019

Why cant we use -13.6Z^2


  • Megha
  • Nov 07, 2018

How it's come?


  • Abhishek upmanyu
  • Aug 23, 2018

Right solution


Add Comment

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 10: Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. Calcula....