Is there any change in the hybridisation | Class 11 Chemistry Chapter Chemical Bonding and Molecular Structure, Chemical Bonding and Molecular Structure NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Chemical Bonding and Molecular Structure. This page offers a step-by-step solution to the specific question from Exercise 1, Question 26: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 26:

Is there any change in the hybridisation of B and N atoms as a result of the following reaction?

BF3 + NH3 → F3B.NH3

 

Answer:

The atomic number of boron is 5 & its electronic configuration in ground state  is 1s2 2s2 2p1, & in excited state is 1s2 2s1 2p2 , this means its one s & 2 p orbital will take part in hybridization to form sp2  hybrid orbital.

Similarly N atom has atomic number of 7, with electronic configuration of 1s2 2s2 2p3 in its ground state & in it excited state it has sp3 hybridization.

Now according to the question Boron & Nitrogen in reactant stage has sp2 & sp3  hybridization respectively, but on the product side an adduct is formed, wherein Boron has changed it s hybridization to sp3 while Nitrogen remains in same sp3 hybridization


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Comments

  • Awer
  • Sep 22, 2019

You explained but no one understands no offence


  • vishnu
  • Dec 25, 2018

i dunno understand that ???


  • Ramesh Kumar
  • May 30, 2018

How can we find hybridization of F3B.NH3


  • Vassudev
  • Aug 26, 2017

There is no change in both the case for hybridisation. This statement is given in a guide.....Which one is true? Why?


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 26: Is there any change in the hybridisation of B and N atoms as a result of the following reaction? ....