Percentage Calculator
Calculate percentage from obtained marks and total marks.
This chapter belongs to a previous NCERT/CBSE curriculum and is not part of the current 2026-27 chapter list. Removed in 2022-23.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter States of Matter. This page offers a step-by-step solution to the specific question from Exercise 1, Question 7:
What will be the pressure exerted by a mixture of 3.2 g of methane and 4.4 g of carbon dioxide contained in a 9 dm3 flask at 27 °C ?
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.What will be the pressure exerted by a mixture of 3.2 g of methane and 4.4 g of carbon dioxide contained in a 9 dm3 flask at 27 °C ?
Given,
Mass of carbon dioxide = 4.4 g
Molar mass of carbon dioxide= 44g/mol
Mass of methane = 3.2g
Molar mass of methane = 16g/mol
Now amount of methane, nCH4 = 3.2/ 16 = 0.2 mol
& amount of CO2 nCO2 = 4.4/ 44 = 0.1 mol
Also we know ,
Pv = (nCH4 + nCO2) RT
OR P X 9 = (0.2 +0.1) x 0.0821 x 300
Or p = 0.3 x 0.0821 x 300 / 9 = 0.821 atm
Hence, the total pressure exerted by the mixture is 0.821 atm
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 7: What will be the pressure exerted by a mixture of 3.2 g of methane and 4.4 g of carbon dioxide conta....
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