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Academic session 2026-27, Chapter 5 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Thermodynamics. This page offers a step-by-step solution to the specific question from Exercise 1, Question 22:
Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard conditions. ΔfH0 = –286 kJ mol–1.
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard conditions. ΔfH0 = –286 kJ mol–1.
It is given that 286 kJ mol-1of heat is evolved on the formation of 1 mol of H2O(l). Thus, an equal amount of heat will be absorbed by the surroundings.
qsurr = +286 kJ mol-1
Entropy change (ΔSsurr) for the surroundings = qsurr / 7
= 286 kJ mol-1 / 298k
ΔSsurr = 959.73 J mol-1K-1
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 22: Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard condit....
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in the above qusetion T does not given but in solution how it can be given to solve it
Great
calculate the bond enthalpy of HCl if enthalpy of H and Cl is 424 kj/mol and 230 kj/mol. the enthalpy of formation of HCl is -91 kj/mol