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Read MoreWelcome to the NCERT Solutions for Class 11 Chemistry - Chapter Equilibrium. This page offers a step-by-step solution to the specific question from Exercise 1, Question 19: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.
A sample of pure PCl5 was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of PCl5 was found to be 0.5 × 10–1 mol L–1. If value of Kc is 8.3 × 10–3, what are the concentrations of PCl3 and Cl2 at equilibrium?
PCl5 (g) ↔ PCl3 (g) + Cl2(g)
Let the concentrations of both PCl3 and Cl2 at equilibrium be x molL-1. The given reaction is:
PCl5 (g) ↔ PCl3 (g) + Cl2(g)
at equilibrium 0.5x10-1molL-1 xmolL-1 xmolL-1
it is given that the value of equilibrium constant, Kc is 8.3x10–3
Now we can write the expression for equilibrium as:

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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 19: A sample of pure PCl5 was introduced into an evacuated vessel at 473 K. After equilibrium was attain....
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