What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition n = 4 to n = 2 of He+ spectrum?
For an atom = 1/λ = RHZ2 (1/n12-1/n22)
For He+ spectrum Z = 2, n2=4, n1= 2
Therefore = 1/λ = RH x 4(1/22-1/42) = 3RH/4
For hydrogen spectrum = 3RH/4, Z = 1
Therefore = 1/λ = RH X 1(1/n12-1/n22)
Or
RH (1/n12-1/n22) = 3RH/4
Or
1/n12-1/n22 = 3/4
Which can be so for n1=1 & n2 = 2, i.e the transition is from n = 2 to n=1
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(d) n = 4; l =3.
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(b) NaHSO4
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(d) K2MnO4
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(ii) whose value is independent of path
(iii) used to determine pressure volume work
(iv) whose value depends on temperature only.
A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased.
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c) What happens when equilibrium is restored finally and what will be the final vapour pressure?
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(d) C6H5–CHO
(e) C6 H5 - C+H2
(f) CH3CH = CHC+H2
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(i) Write the concentration ratio (reaction quotient), Qc, for this reaction (note: water is not in excess and is not a solvent in this reaction)
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(iii) Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293 K, 0.214 mol of ethyl acetate is found after sometime. Has equilibrium been reached?
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Calculate the ionization constants of the corresponding conjugate base.
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(b) Boric acid is added to water,
(c) Aluminium is treated with dilute NaOH,
(d) BF3 is reacted with ammonia?
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Nice i liked the answer
How n1=1andn2=2
How n=1 n=2
Wow nice...
Nice approach to solve question... Really nice
How n1=1 and n2=2
how n1 = 1 and n2 so on????