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Question 25

How are 0.50 mol Na2CO3 and 0.50 M Na2CO3 different?

Answer

Molar mass of Na2CO3 = (2 × 23) + 12.00 + (3× 16) = 106 g mol–1

 

1 mole of Na2CO3 = 106 g

 

0.5 mol of Na2CO= 53 g Na2CO3

 

⇒ 0.50 M of Na2CO3 = 0.50 mol/L Na2CO3

 

Hence, 0.50 mol of Na2CO3 is present in 1 L of water or 53 g of Na2CO3 is present in 1 L of water.

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