Question 19

Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

Answer

There are one octahedral hole for each atom in hexagonal close packed arrangement. If the no. of oxide ions per unit cell = 1.

   then no. of fe3+ ions = 2/3 x octahedual holes 

            = 2/3 x 1 = 2/3

   formula of the compound = fe2/3 Oor fe2O3

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