What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition n = 4 to n = 2 of He+ spectrum?
For an atom = 1/λ = RHZ2 (1/n12-1/n22)
For He+ spectrum Z = 2, n2=4, n1= 2
Therefore = 1/λ = RH x 4(1/22-1/42) = 3RH/4
For hydrogen spectrum = 3RH/4, Z = 1
Therefore = 1/λ = RH X 1(1/n12-1/n22)
Or
RH (1/n12-1/n22) = 3RH/4
Or
1/n12-1/n22 = 3/4
Which can be so for n1=1 & n2 = 2, i.e the transition is from n = 2 to n=1
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Please tell me more about hit and trial
Nice i liked the answer
How n1=1andn2=2
How n=1 n=2
Wow nice...
Nice approach to solve question... Really nice
How n1=1 and n2=2
how n1 = 1 and n2 so on????