Question 2

Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter?

Answer

Current in a circuit is measured through an ammeter that should be connected in the circuit in series with the resistors. To measure the potential difference across the 12 Ω resistor, a voltmeter should be connected parallel to this resistor, as shown in the following figure.

The resistances are connected in series.

Ohm’s law can be used to obtain the readings of ammeter and voltmeter. According to it

V = IR,

Here ,

V Potential difference= 6 V

Current flowing through the circuit/resistors = I

Resistance of the circuit, R = 5+8+12 = 25 Ω

Potential difference across 12 Ω resistor = V_I

Current flowing through the 12 Ω resistor, I = 0.24 A

Therefore, using Ohm’s law, we obtain

V_I = IR = 0.24x12 = 2.88 V

So the reading of the ammeter will be 0.24 A.

The reading of the voltmeter will be 2.88 V.

Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 Ω resistor. What would be the readings in the ammeter and the voltmeter?

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