Question 27

The equilibrium constant for the following reaction is 1.6 ×105 at 1024K

H2(g) + Br2(g)2HBr(g)

Find the equilibrium pressure of all gases if 10.0 bar of HBr is introduced into a sealed container at 1024K.

Answer

Given,kp for the reaction i.e., H2(g) + Br2(g)2HBr(g)  is 1.6 ×105

Therefore, for the reaction

2HBr(g) H2(g) + Br2(g)

the equilibrium constant will be,

K'p = 1/Kp

     = 1/1.6 ×105

      = 6.25x10-6

Now, let p be the pressure of both H2 and Br2 at equilibrium.

                    2HBr(g) H2(g) + Br2(g)

Initial Conc.      10             0         0

at equilibrium 10-2p           p         p

Now, we can write,

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