How much time would it take to distribute one Avogadro number of wheat grains, if 1010 grains are distributed each second?
We know , Avogadro number = 6.023 × 1023
Therefore , time taken for distributing the grains
= (6.023 × 1023 x 1) / 1010 = 6.023 x 1013 s
By Converting these seconds into years, we get
= (6.023 x 1013) / (60 x60x24x365)
= 1,90,9800 y
Hence, the time taken would be 1.909 x 106 years.
What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?
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(b) NaHSO4
(c) H4P2O7
(d) K2MnO4
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(f) NaBH4
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(iii) used to determine pressure volume work
(iv) whose value depends on temperature only.
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c) What happens when equilibrium is restored finally and what will be the final vapour pressure?
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(d) C6H5CHO(l) + 2Cu2+(aq) + 5OH-(aq) → No change observed.
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Draw diagrams showing the formation of a double bond and a triple bond between carbon atoms in C2H4 and C2H2 molecules.
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Why the Avogadro's no. Divide by 10^10
This ans is correct . But it can be more explained clearly
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How to convert seconds into years
Respected sir If a man counts four grain of wheat each second than how much time he takes to count one mol of wheat grain?